231 research outputs found

    Revisiting T-Norms for Type-2 Fuzzy Sets

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    Let L\mathbf{L} be the set of all normal and convex functions from [0,1]{[0, 1]} to [0,1]{[0, 1]}. This paper proves that t{t}-norm in the sense of Walker-and-Walker is strictly stronger that tr{t_r}-norm on L\mathbf{L}, which is strictly stronger than t{t}-norm on L\mathbf{L}. Furthermore, let ⋏{\curlywedge} and β‹Ž{\curlyvee} be special convolution operations defined by (f⋏g)(x)=sup⁑{f(y)⋆g(z):yβ–³z=x}, {(f\curlywedge g)(x)=\sup\left\{f(y)\star g(z): y\vartriangle z=x\right\},} (fβ‹Žg)(x)=sup⁑{f(y)⋆g(z):yΒ β–½Β z=x}, {(f\curlyvee g)(x)=\sup\left\{f(y)\star g(z): y\ \triangledown\ z=x\right\},} for f,g∈Map([0,1],[0,1]){f, g\in Map([0, 1], [0, 1])}, where β–³{\vartriangle} and β–½{\triangledown} are respectively a t{t}-norm and a t{t}-conorm on [0,1]{[0, 1]} (not necessarily continuous), and ⋆{\star} is a binary operation on [0,1]{[0, 1]}. Then, it is proved that if the binary operation ⋏{\curlywedge} is a tr{t_r}-norm (resp., β‹Ž{\curlyvee} is a tr{t_r}-conorm), then β–³{\vartriangle} is a continuous t{t}-norm (resp., β–½{\triangledown} is a continuous t{t}-conorm) on [0,1]{[0, 1]}, and ⋆{\star} is a t{t}-norm on [0,1]{[0, 1]}.Comment: arXiv admin note: text overlap with arXiv:1908.10532, arXiv:1907.1239
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